一款html5 canvas实现的图片玻璃碎片特效
一款html5 canvas实现的图片玻璃碎片特效
发布时间:2017-01-07 来源:查字典编辑
摘要:今天要为大家带来一款html5canvas实现的图片玻璃碎片特效。图片以玻璃碎片的形式出现到界面中,然后似玻璃被打碎的效果渐消息。效果图如下...

今天要为大家带来一款html5 canvas实现的图片玻璃碎片特效。图片以玻璃碎片的形式出现到界面中,然后似玻璃被打碎的效果渐消息。效果图如下:

1

html代码:

<img src="city_copy.jpg" id="src_img">

<div id="container">

<div>

<script src="delaunay.js"></script>

<script src="TweenMax.min.js"></script>

js代码:

// canvas settings

var imageWidth = 768,

imageHeight = 485;

var vertices = [],

indices,

boxes = [];

var image,

fragments = [],

container = document.getElementById('container');

window.onload = function () {

image = document.getElementById('src_img');

triangulate();

makeBoxes();

makeFragments();

};

function triangulate() {

var x,

y,

dx = imageWidth / 8,

dy = imageHeight / 8,

offset = 0.5;

for (var i = 0; i <= imageWidth; i += dx) {

for (var j = 0; j <= imageHeight; j += dy) {

if (i && (i !== imageWidth)) x = i + randomRange(-dx * offset, dx * offset);

else x = i;

if (j && (j !== imageHeight)) y = j + randomRange(-dy * offset, dy * offset);

else y = j;

vertices.push([x, y]);

}

}

indices = Delaunay.triangulate(vertices);

}

function makeBoxes() {

var p0, p1, p2,

xMin, xMax,

yMin, yMax;

for (var i = 0; i < indices.length; i += 3) {

p0 = vertices[indices[i + 0]];

p1 = vertices[indices[i + 1]];

p2 = vertices[indices[i + 2]];

xMin = Math.min(p0[0], p1[0], p2[0]);

xMax = Math.max(p0[0], p1[0], p2[0]);

yMin = Math.min(p0[1], p1[1], p2[1]);

yMax = Math.max(p0[1], p1[1], p2[1]);

boxes.push({

x: xMin,

y: yMin,

w: xMax - xMin,

h: yMax - yMin

});

}

}

function makeFragments() {

var p0, p1, p2,

box,

fragment;

TweenMax.set(container, { perspective: 500 });

var tl0 = new TimelineMax({ repeat: -1 });

for (var i = 0; i < indices.length; i += 3) {

p0 = vertices[indices[i + 0]];

p1 = vertices[indices[i + 1]];

p2 = vertices[indices[i + 2]];

box = boxes[i / 3];

fragment = new Fragment(p0, p1, p2, box);

var rx = randomRange(30, 60) * ((i % 2) ? 1 : -1);

var ry = randomRange(30, 60) * ((i % 2) ? -1 : 1);

var tl1 = new TimelineMax();

TweenMax.set(fragment.canvas, {

y: box.y - 1000

});

tl1.to(fragment.canvas, randomRange(0.9, 1.1), {

y: box.y,

ease: Back.easeOut

});

tl1.to(fragment.canvas, 0.5, {

z: -100,

ease: Cubic.easeIn,

delay: 0.4

});

tl1.to(fragment.canvas, randomRange(1, 1.2), {

rotationX: rx,

rotationY: ry,

z: 250,

alpha: 0,

ease: Cubic.easeOut

});

tl0.insert(tl1);

fragments.push(fragment);

container.appendChild(fragment.canvas);

}

}

function randomRange(min, max) {

return min + (max - min) * Math.random();

}

Fragment = function (v0, v1, v2, box) {

this.v0 = v0;

this.v1 = v1;

this.v2 = v2;

this.box = box;

this.canvas = document.createElement('canvas');

this.canvas.width = this.box.w;

this.canvas.height = this.box.h;

this.canvas.style.width = this.box.w + 'px';

this.canvas.style.height = this.box.h + 'px';

this.ctx = this.canvas.getContext('2d');

TweenMax.set(this.canvas, {

x: this.box.x,

y: this.box.y

});

this.ctx.translate(-this.box.x, -this.box.y);

this.ctx.beginPath();

this.ctx.moveTo(this.v0[0], this.v0[1]);

this.ctx.lineTo(this.v1[0], this.v1[1]);

this.ctx.lineTo(this.v2[0], this.v2[1]);

this.ctx.closePath();

this.ctx.clip();

this.ctx.drawImage(image, 0, 0);

}; //@ sourceURL=pen.js

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