将选择的图片显示在listview中,并显示filename,path和type的简单实例
发布时间:2016-12-29 来源:查字典编辑
摘要:复制代码代码如下:if(openFileDialog1.ShowDialog()==DialogResult.OK){listView1.I...
复制代码 代码如下:
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
listView1.Items.Clear();
string[] files = openFileDialog1.FileNames; //定义一个数组,获取选择的文件
string[] fileinfo = new string[3]; //定义一个数组,用于存储文件信息
for (int i = 0; i < files.Length; i++) //遍历文件数组
{
string path = files[i].ToString(); //获取文件路径
//截取文件名字
string fileName = path.Substring(path.LastIndexOf("") + 1, path.Length - 1 - path.LastIndexOf(""));
//截取文件类型
string fileType = fileName.Substring(fileName.LastIndexOf(".") + 1, fileName.Length - 1 - fileName.LastIndexOf("."));
fileinfo[0] = fileName;
fileinfo[1] = path;
fileinfo[2] = fileType;
ListViewItem lvi = new ListViewItem(fileinfo);
listView1.Items.Add(lvi);
}
}
注释:ListView1, View 属性为Details
OpenFileDialog1,Multiselect属性为true