本文实例讲述了Python打印scrapy蜘蛛抓取树结构的方法。分享给大家供大家参考。具体如下：

通过下面这段代码可以一目了然的知道scrapy的抓取页面结构，调用也非常简单

#!/usr/bin/env python import fileinput, re from collections import defaultdict def print_urls(allurls, referer, indent=0): urls = allurls[referer] for url in urls: print ' '*indent + referer if url in allurls: print_urls(allurls, url, indent+2) def main(): log_re = re.compile(r'<GET (.*?)> (referer: (.*?))') allurls = defaultdict(list) for l in fileinput.input(): m = log_re.search(l) if m: url, ref = m.groups() allurls[ref] += [url] print_urls(allurls, 'None') main()

希望本文所述对大家的Python程序设计有所帮助。