实现获取http内容的php函数分享
实现获取http内容的php函数分享
发布时间:2016-12-29 来源:查字典编辑
摘要:复制代码代码如下:

复制代码 代码如下:

<?php

function http_open($url, $data, $cookie = null, $method = "GET", $timeout = 60) {

$options = array();

$options['http']['method'] = $method;

$options['http']['user_agent'] = $_SERVER['HTTP_USER_AGENT'];

$options['http']['timeout'] = $timeout;

if($method == "POST") :

$length = strlen($data);

$options['http']['header'] = "Content-type: application/x-www-form-urlencodedrn".

"Content-Length: {$length}rn".

"P3P: CP="CURa ADMa DEVa PSAo PSDo OUR BUS UNI PUR INT DEM STA PRE COM NAV OTC NOI DSP COR"rn".

"cookie: {$cookie}rn".

"Connection: closern";

$options['http']['content'] = $data;

else:

$options['http']['header'] = "Content-type: application/x-www-form-urlencodedrn".

"P3P: CP="CURa ADMa DEVa PSAo PSDo OUR BUS UNI PUR INT DEM STA PRE COM NAV OTC NOI DSP COR"rn".

"cookie: {$cookie}rn".

"Connection: closern";

endif;

$context = stream_context_create($options);

return file_get_contents($url, 0, $context);

}

echo http_open("http://localhost/1.php", "username=haowei", "id=5", "POST");

推荐文章
猜你喜欢
附近的人在看
推荐阅读
拓展阅读
相关阅读
网友关注
最新php教程学习
热门php教程学习
编程开发子分类