复制代码 代码如下:
<?php
$password = "1234"; // 这里是密码
$p = "";
if(isset($_COOKIE["isview"]) and $_COOKIE["isview"] == $password){
$isview = true;
}else{
if(isset($_POST["pwd"])){
if($_POST["pwd"] == $password){
setcookie("isview",$_POST["pwd"],time()+3600*3);
$isview = true;
}else{
$p = (empty($_POST["pwd"])) ? "需要密码才能查看，请输入密码。" : "密码不正确，请重新输入。";
}
}else{
$isview = false;
$p = "请输入密码查看，获取密码可联系我。";
}
}
if($isview){ ?>
这里是密码成功后显示的地方
<?php }else{ ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns=" http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta http-equiv="pragma" content="no-cache" />
<meta http-equiv="cache-control" content="no-cache" />
<meta http-equiv="expires" content="0" />
<title>查字典教程网提醒你输入密码</title>
<>
<style type="text/css">
<>
</style>
<div>
<div>
<form action="?yes" method="post">输入查看密码
<input type="password" name="pwd" /> <input type="submit" value="查看" />
</form>
<?php echo $p; ?>
</div>
</div>
<?php
} ?>
</body>
</html>