以查询前20到30条为例,主键名为id

方法一: 先正查,再反查

select top 10 * from (select top 30 * from tablename order by id asc) A order by id desc

方法二: 使用left join

select top 10 A.* from tablename A

left outer join (select top 20 * from tablename order by id asc) B

on A.id = B.id

where B.id is null

order by A.id asc

方法三: 使用not exists

select top 10 * from tablename A

where id not exists

(select top 20 * from tablename B on A.id = B.id)

方法四: 使用not in

select top 10 * from tablename

where id not in

(select top 20 id from tablename order by id asc)

order by id asc

方法五: 使用rank()

select id from

(select rank() over(order by id asc) rk, id from tablename) T

where rk between 20 and 30

中第五种方法看上去好像没有问题,查了下文档,当over()用于rank/row_number时,整型列不能描述一个列,所以会产生非预期的效果. 待考虑下,有什么办法可以修改为想要的结果.