如果有一个字符串 eg: "sun,star,moon,clouds",想要在MS SQL中根据给定的分隔符','把这个字符串分解成各个元素[sun] [star] [moon] [clouds]，如何实现呢？为此，创建一个Function,代码如下:

复制代码 代码如下:

CREATE FUNCTION [dbo].[Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1))

RETURNS @temptable TABLE (items VARCHAR(8000))

AS

BEGIN

DECLARE @idx INT

DECLARE @slice VARCHAR(8000)

SELECT @idx = 1

IF len(@String)<1 OR @String IS NULL RETURN

while @idx!= 0

BEGIN

SET @idx = charindex(@Delimiter,@String)

IF @idx!=0

SET @slice = LEFT(@String,@idx - 1)

ELSE

SET @slice = @String

IF(len(@slice)>0)

INSERT INTO @temptable(Items) VALUES(@slice)

SET @String = RIGHT(@String,len(@String) - @idx)

IF len(@String) = 0 break

END

RETURN

END

示例：如果输入

SELECT * FROM dbo.Split_StrByDelimiter('sun,star,moon,clouds',',')

结果返回

sun

star

moon

clouds

在上面的代码做变形，返回有多少个元素

复制代码 代码如下:

CREATE FUNCTION [dbo].[GetCount_Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1))

RETURNS INT

AS

BEGIN

DECLARE @temptable TABLE (items VARCHAR(8000))

DECLARE @SplitCount INT

DECLARE @idx INT

DECLARE @slice VARCHAR(8000)

SELECT @idx = 1

IF len(@String)<1 OR @String IS NULL RETURN 0

while @idx!= 0

BEGIN

SET @idx = charindex(@Delimiter,@String)

IF @idx!=0

SET @slice = LEFT(@String,@idx - 1)

ELSE

SET @slice = @String

IF(len(@slice)>0)

INSERT INTO @temptable(Items) VALUES(@slice)

SET @String = RIGHT(@String,len(@String) - @idx)

IF len(@String) = 0 break

END

SET @SplitCount=(SELECT COUNT(*) FROM @temptable)

RETURN @SplitCount

END

示例

SELECT dbo.GetCount_Split_StrByDelimiter('sun,star,moon,clouds',',')

结果返回

4