复制代码 代码如下:

@echo off

:: 查找形如 <input name=id value=1842 type=hidden> 的记录中

:: 的第一个数字串

:: 通过探测每一个字符的类型来获取，但是效率十分低下

:: code by jm 2006-10-16 CMD@XP

set num=0

setlocal enabledelayedexpansion

for /f "delims=" %%i in (input.txt) do call :intercept "%%i"

echo value=%str_%

pause

goto :eof

:intercept

set str=%1

set str=%str:~2,-2%

if not "%str%"=="" echo. "%str:~0,1%"|findstr "[0-9]">nul && (

set num=1&set str_=!str_!%str:~0,1%&&call :intercept " !str:~1! ")||(

if %num% equ 0 call :intercept " !str:~1! "

)

goto :eof

无奈何的方案，不依赖字符前后关系，会获取 value= 后的任意值，速度非常快

更能处理形如input type=hidden name=id VALUE=465974855 <input type=hidden name=id value="1820988170"><input type=hidden name=id value=1008964101>

的字符串

@echo off

setlocal enabledelayedexpansion

FOR /f "delims=" %%i in (input.txt) do (

set "t=%%i"

set "t=!t:<= !"

set "t=!t:>= !"

set "t=!t:&= !"

set "t=!t:|= !"

call :sub !t !

)

pause

goto :eof

:sub

if "%1" == "" exit /b

if "%F%" == "1" echo %1 &set F=0

if "%1" == "value" set F=1

shift

goto sub