python操作gmail实例
python操作gmail实例
发布时间:2016-12-28 来源:查字典编辑
摘要:本文实例讲述了python操作gmail的方法。分享给大家供大家参考。具体实现方法如下:复制代码代码如下:importimaplib,rec...

本文实例讲述了python操作gmail的方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:import imaplib, re

class pygmail(object):

def __init__(self):

self.IMAP_SERVER='imap.gmail.com'

self.IMAP_PORT=993

self.M = None

self.response = None

self.mailboxes = []

def login(self, username, password):

self.M = imaplib.IMAP4_SSL(self.IMAP_SERVER, self.IMAP_PORT)

rc, self.response = self.M.login(username, password)

return rc

def get_mailboxes(self):

rc, self.response = self.M.list()

for item in self.response:

self.mailboxes.append(item.split()[-1])

return rc

def get_mail_count(self, folder='Inbox'):

rc, self.response = self.M.select(folder)

return self.response[0]

def get_unread_count(self, folder='Inbox'):

rc, self.response = self.M.status(folder, "(UNSEEN)")

unreadCount = re.search("UNSEEN (d+)", self.response[0]).group(1)

return unreadCount

def get_imap_quota(self):

quotaStr = self.M.getquotaroot("Inbox")[1][1][0]

r = re.compile('d+').findall(quotaStr)

if r == []:

r.append(0)

r.append(0)

return float(r[1])/1024, float(r[0])/1024

def get_mails_from(self, uid, folder='Inbox'):

status, count = self.M.select(folder, readonly=1)

status, response = self.M.search(None, 'FROM', uid)

email_ids = [e_id for e_id in response[0].split()]

return email_ids

def get_mail_from_id(self, id):

status, response = self.M.fetch(id, '(body[header.fields (subject)])')

return response

def rename_mailbox(self, oldmailbox, newmailbox):

rc, self.response = self.M.rename(oldmailbox, newmailbox)

return rc

def create_mailbox(self, mailbox):

rc, self.response = self.M.create(mailbox)

return rc

def delete_mailbox(self, mailbox):

rc, self.response = self.M.delete(mailbox)

return rc

def logout(self):

self.M.logout()

if __name__ =="__main__":

demo=pygmail()

demo.login("renwenchao888@gmail.com","qqq191430791")

mailBoxex=demo.get_mailboxes()

for i in demo.response:

print i

demo.logout()

希望本文所述对大家的Python程序设计有所帮助。

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