本文实例讲述了python实现在无须过多援引的情况下创建字典的方法。分享给大家供大家参考。具体实现方法如下：

1.使用itertools模块

import itertools the_key = ['ab','22',33] the_vale = ['aaaa',"dddddddd",'22222222222'] d = dict(itertools.izip(the_key,the_vale)) print d

2.加参数

dict = dict(red = 1,bule = 2,yellow = 3) print dict

结果为：{'yellow': 3, 'bule': 2, 'red': 1}

3.使用内置的zip函数

zip([iterable,...])返回一个列表，

the_key = ['ab','22',33] the_vale = ['aaaa',"dddddddd",'22222222222'] dict2 = dict(zip(the_key,the_vale)) print type(zip(the_key,the_vale)) print dict2

结果：

<type 'list'> {33: '22222222222', 'ab': 'aaaa', '22': 'dddddddd'}

4.dict的fromkeys函数

创建的每个键有相同的value

fromkeys(seq[,value]) Create a new dictionary with keys from seq and values set to value. the_key = ['ab','22',33] the_vale = 0 d = dict.fromkeys(the_key,the_vale) print

结果：{33: 0, 'ab': 0, '22': 0}

import string count_by_letter = dict.fromkeys(string.ascii_lowercase,0) print count_by_letter

结果：

{'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}

希望本文所述对大家Python程序设计的学习有所帮助。