使用python实现递归版汉诺塔示例(汉诺塔递归算法)
使用python实现递归版汉诺塔示例(汉诺塔递归算法)
发布时间:2016-12-28 来源:查字典编辑
摘要:利用python实现的汉诺塔。带有图形演示复制代码代码如下:fromtimeimportsleepdefdisp_sym(num,sym):...

利用python实现的汉诺塔。带有图形演示

复制代码 代码如下:

from time import sleep

def disp_sym(num, sym):

print(sym*num, end='')

#recusion

def hanoi(a, b, c, n, tray_num):

if n == 1:

move_tray(a, c)

disp(tray_num)

sleep(0.7)

else:

hanoi(a, c, b, n-1, tray_num)

move_tray(a, c)

disp(tray_num)

sleep(0.7)

hanoi(b, a, c, n-1, tray_num)

def move_tray(a, b):

for i in a:

if i != 0:

for j in b:

if j != 0:

b[b.index(j) - 1] = i

a[a.index(i)] = 0

return

b.append(i)

b.pop(0)

a[a.index(i)] = 0

return

def disp(tray_num):

global a, b, c

for i in range(tray_num):

for j in ['a', 'b', 'c']:

disp_sym(5, ' ')

eval('disp_sym(tray_num - ' + j + "[i], ' ')")

eval('disp_sym(' + j + "[i], '=')")

disp_sym(1, '|')

eval('disp_sym(' + j + "[i], '=')")

eval('disp_sym(tray_num - ' + j + "[i], ' ')")

print()

print('---------------------------------------------------------------------------')

tray_num=int(input("Please input the number of trays:"))

tray=[]

for i in range(tray_num):

tray.append(i + 1)

a=[0]*tray_num

b=a[:]

c=a[:]

a = tray[:]

disp(tray_num)

hanoi(a, b, c, tray_num, tray_num)

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