为确保php页面在后台运行，写了一个监控脚本，假设程序异常退出，那么可以自动重启。

shell脚本/usr/local/scripts/receve.sh内容：

#!/bin/bash #funtion:keep receve.php running PHP="/usr/local/php5/bin/php" PROGRAM="receve.php" #start dameo $PHP /home/httpd/$PROGRAM >>/usr/local/scripts/phpshell/receve.out & chpid="$!"; echo "$chpid" > /usr/local/scripts/phpshell/receve.sid echo "child pid is $chpid" echo "status is $" while [ 1 ] do wait $chpid exitstatus="$"child pid=$chpid is gone, $exitstatus" >>/usr/local/scripts/phpshell/receve.php_error.log echo `date` >> /usr/local/scripts/phpshell/receve.php_error.log echo "**************************" >>/usr/local/scripts/phpshell/receve.php_error.log sleep 10 $PHP /home/httpd/$PROGRAM >> /usr/local/scripts/phpshell/receve.out & chpid="$!"; echo "$chpid" > /usr/local/scripts/phpshell/receve.sid echo "next child pid is $chpid" echo "next status is $" done

需要保证监控脚本正常运行，在每天凌晨自动重启脚本/usr/local/scripts/restart_r.sh，写入crontab：

#!/bin/bash echo "" >/tmp/receve_pid.txt /bin/ps ax | /bin/grep "receve.sh" | /bin/grep -v "grep" | /bin/awk '{print $1}' >/tmp/receve_pid.txt no1pid=`cat /tmp/receve_pid.txt | sort -r` no2pid=`cat /usr/local/scripts/phpshell/receve.sid | sort -r` if [ -z $no1pid ];then echo "receve.sh pid is null, receve.sh is not running." else /bin/kill -9 "$no1pid" echo "receve.sh killed" fi sleep 3 if [ -z $no2pid ];then echo "receve.php pid is null, receve.php is not running." else /bin/kill -9 "$no2pid" echo "receve.php killed" fi rm -rf /usr/local/scripts/phpshell/receve.sid sleep 3 /usr/local/scripts/receve.sh > /dev/null &

crontab：

复制代码 代码如下:

#restart receve.sh

10 00 * * * /usr/local/scripts/restart_r.sh

注意：脚本命名要避免重复，避免自己kill掉自己的进程。