1、确定某年某月有多少天

实现原理：先利用DATEDIFF取得当前月的第一天，再将月份加一取得下月第一天，然后减去1分钟，再取日期的

天数部分，即为当月最大日期，也即当月天数

CREATE FUNCTION DaysInMonth ( @date datetime ) Returns int

AS

BEGIN

RETURN Day(dateadd(mi,-3,DATEADD(m, DATEDIFF(m,0,@date)+1,0)))

END

调用示例：

select dbo.DaysInMonth ('2006-02-03')

(2)计算哪一天是本周的星期一

SELECT DATEADD(week, DATEDIFF(week,'1900-01-01',getdate()), '1900-01-01') --返回2006-11-06 00:00:00.000

或

SELECT DATEADD(week, DATEDIFF(week,0,getdate()),0)

(3)当前季度的第一天

SELECT DATEADD(quarter, DATEDIFF(quarter,0,getdate()), 0)—返回2006-10-01 00:00:00.000

(4)一个季度多少天

declare @m tinyint,@time smalldatetime

select @m=month(getdate())

select @m=case when @m between 1 and 3 then 1

when @m between 4 and 6 then 4

when @m between 7 and 9 then 7

else 10 end

select @time=datename(year,getdate())+'-'+convert(varchar(10),@m)+'-01'

select datediff(day,@time,dateadd(mm,3,@time)) —返回92