如何在Sql2008中获取表字段属性和注释_mssql数据库教程-查字典教程网
如何在Sql2008中获取表字段属性和注释
如何在Sql2008中获取表字段属性和注释
发布时间:2018-02-01 来源:查字典编辑
摘要:如何在Sql2008中获取表字段属性和注释?selectb.[value]fromsys.columnsaleftjoinsys.exten...

  如何在Sql2008中获取表字段属性和注释?

  select b.[value] from sys.columns a left join sys.extended_properties b on a.object_id=b.major_id

  and a.column_id=b.minor_id inner join sysobjects c on a.column_id=c.id

  and a.[name]='列名' and c.[name]='表名'

  SELECT

  表名=case when a.colorder=1 then d.name else '' end,

  表说明=case when a.colorder=1 then isnull(f.value,'') else '' end,

  字段序号=a.colorder,

  字段名=a.name,

  标识=case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,

  主键=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and name in (

  SELECT name FROM sysindexes WHERE indid in(

  SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid

  ))) then '√' else '' end,

  类型=b.name,

  占用字节数=a.length,

  长度=COLUMNPROPERTY(a.id,a.name,'PRECISION'),

  小数位数=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),

  允许空=case when a.isnullable=1 then '√'else '' end,

  默认值=isnull(e.text,''),

  字段说明=isnull(g.[value],'')

  FROM syscolumns a

  left join systypes b on a.xusertype=b.xusertype

  inner join sysobjects d on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'

  left join syscomments e on a.cdefault=e.id

  left join sys.extended_properties g on a.id=g.major_id and a.colid=g.minor_id

  left join sys.extended_properties f on d.id=f.major_id and f.minor_id=0

  --where d.name='orders' --如果只查询指定表,加上此条件

  order by a.id,a.colorder

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