python双向链表实现实例代码_python教程-查字典教程网
python双向链表实现实例代码
python双向链表实现实例代码
发布时间:2017-01-07 来源:查字典编辑
摘要:示意图:python双向链表实现代码:复制代码代码如下:#!/usr/bin/python#-*-coding:utf-8-*-classN...

示意图:

python双向链表实现代码:

复制代码 代码如下:

#!/usr/bin/python

# -*- coding: utf-8 -*-

class Node(object):

def __init__(self,val,p=0):

self.data = val

self.next = p

self.prev = p

class LinkList(object):

def __init__(self):

self.head = 0

def __getitem__(self, key):

if self.is_empty():

print 'linklist is empty.'

return

elif key <0 or key > self.getlength():

print 'the given key is error'

return

else:

return self.getitem(key)

def __setitem__(self, key, value):

if self.is_empty():

print 'linklist is empty.'

return

elif key <0 or key > self.getlength():

print 'the given key is error'

return

else:

self.delete(key)

return self.insert(key)

def initlist(self,data):

self.head = Node(data[0])

p = self.head

for i in data[1:]:

node = Node(i)

p.next = node

node.prev = p

p = p.next

def getlength(self):

p = self.head

length = 0

while p!=0:

length+=1

p = p.next

return length

def is_empty(self):

if self.getlength() ==0:

return True

else:

return False

def clear(self):

self.head = 0

def append(self,item):

q = Node(item)

if self.head ==0:

self.head = q

else:

p = self.head

while p.next!=0:

p = p.next

p.next = q

q.prev = p

def getitem(self,index):

if self.is_empty():

print 'Linklist is empty.'

return

j = 0

p = self.head

while p.next!=0 and j <index:

p = p.next

j+=1

if j ==index:

return p.data

else:

print 'target is not exist!'

def insert(self,index,item):

if self.is_empty() or index<0 or index >self.getlength():

print 'Linklist is empty.'

return

if index ==0:

q = Node(item,self.head)

self.head = q

p = self.head

post = self.head

j = 0

while p.next!=0 and j<index:

post = p

p = p.next

j+=1

if index ==j:

q = Node(item,p)

post.next = q

q.prev = post

q.next = p

p.prev = q

def delete(self,index):

if self.is_empty() or index<0 or index >self.getlength():

print 'Linklist is empty.'

return

if index ==0:

q = Node(item,self.head)

self.head = q

p = self.head

post = self.head

j = 0

while p.next!=0 and j<index:

post = p

p = p.next

j+=1

if index ==j:

post.next = p.next

p.next.prev = post

def index(self,value):

if self.is_empty():

print 'Linklist is empty.'

return

p = self.head

i = 0

while p.next!=0 and not p.data ==value:

p = p.next

i+=1

if p.data == value:

return i

else:

return -1

l = LinkList()

l.initlist([1,2,3,4,5])

print l.getitem(4)

l.append(6)

print l.getitem(5)

l.insert(4,40)

print l.getitem(3)

print l.getitem(4)

print l.getitem(5)

l.delete(5)

print l.getitem(5)

l.index(5)

结果为;

5

6

4

40

5

6

和单链表结果一样。

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