我有以下几行：

d:ProjectsqqqDevelopmentqqq.MySol1.sln

d:ProjectsqqqqqqDevelopmentqqqMySol2.sln

d:ProjectsqqqDevelopmentMyInstaller.sln

d:ProjectsqqqqqqDevelopmentMyInstaller.sln

d:ProjectsDevelopmentMyInstaller.sln

我需要一个正则表达式，这将导致捕获：

Line 1: Development and MySol1.sln

Line 2: Development and MySol2.sln

Line 3: Development and MyInstaller.sln

Line 4: Development and MyInstaller.sln

Line 5: Development and MyInstaller.sln

因此，一个正则表达式，将删除（忽略）字qqq从行。 我一直在试图与调节，并有部分的解决方案：

复制代码 代码如下:

.*(?<A>.*).{3}(?<B>.*)

这导致：

Line 1: Development and .MySol1.sln

Line 2: qqqDevelopment and MySol2.sln

Line 3: Development and nstaller.sln

Line 4: Development and nstaller.sln

Line 5: Development and nstaller.sln

因此，.{3}应固定

1.我认为，应该工作：

.*(?:qqq)?(?<A>.*)(?:qqq)?(?<B>.*)