复制代码 代码如下:

---1.平均销售等待时间

---有一张Sales表，其中有销售日期与顾客两列，现在要求使用一条SQL语句实现计算

--每个顾客的两次购买之间的平均天数

--假设：在同一个人在一天中不会购买两次

create table sales

(

custname varchar(10) not null,

saledate datetime not null

)

go

insert sales

select '张三','2010-1-1' union

select '张三','2010-11-1' union

select '张三','2011-1-1' union

select '王五','2010-2-1' union

select '王五','2010-4-1' union

select '李四','2010-1-1' union

select '李四','2010-5-1' union

select '李四','2010-9-1' union

select '李四','2011-1-1' union

select '赵六','2010-1-1' union

select '钱途','2010-1-1' union

select '钱途','2011-3-1' union

select '张三','2011-9-1'

go

select custname,DATEDIFF(d,min(saledate),max(saledate))/(COUNT(*)-1) as avgday

from sales

group by custname

having count(*)>1

go

select custname,case when count(*)>1 then DATEDIFF(d,min(saledate),max(saledate))/(COUNT(*)-1)

else DATEDIFF(d,min(saledate),max(saledate)) end

as avgday

from sales

group by custname

--having count(*)>1

go

drop table sales