Shell实现的iptables管理脚本分享_linuxshell教程-查字典教程网
Shell实现的iptables管理脚本分享
Shell实现的iptables管理脚本分享
发布时间:2016-12-28 来源:查字典编辑
摘要:以前的脚本是用save模式,现在把命令附加到一个文件里面,这样的话,可以方便的二次修改什么的脚本基本是这样的,大家可以跟自己的情况再次修改~...

以前的脚本是用save模式,现在把命令附加到一个文件里面,这样的话,可以方便的二次修改什么的

脚本基本是这样的,大家可以跟自己的情况再次修改~ 增加功能什么的。

复制代码 代码如下:

#!/bin/bash

while true

do

clear

echo "----------------------menu----------------------"

echo "(1) service iptables restart"

echo "(2) iptables add"

echo "(3) iptables delete"

echo "(4) iptables stop"

echo "(5) iptables save(不推荐使用这种模式)"

echo "(6) iptables status"

echo "(7) iptables ACL list"

echo "(0) exit"

echo "会在当前的目录下生成一个fw.sh文件"

echo "-------------------------------------------------"

echo -n "enter you chose[0-7]:"

read num

if [ ${num} -lt 0 -o ${num} -gt 7 ]

then

echo "this is not between 0-7"

else

if [ "${num}" == "1" ]

then

service iptables restart&

else

if [ "${num}" == "2" ]

#######################################################

then

while [ "1" == "1" ]

do

clear

echo "----------------------add ACL----------------------"

echo "(1) 针对源IP放行添加"

echo "(2) 针对服务器端口放行添加"

echo "(3) 针对有端口和服务的ACL添加(这里要参数IP和端口 例如 0/0 80)"

echo "(4) 自定义添加"

echo "(5) 退回上一级"

echo "-------------------------------------------------"

echo -n "enter you chose[0-4]:"

read aclnum

if [ "${aclnum}" == "1" ]

then

read ip

iptables -A INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT

echo "iptables -A INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "2" ]

then

rad ip

iptables -A INPUT -p tcp --dport ${IP} -j ACCEPT

echo "iptables -A INPUT -p tcp --dport ${IP} -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "3" ]

then

read ip port

iptables -A INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT

echo "iptables -A INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "4" ]

then

read addacl

`${addacl}`

service iptables save

else

break

fi

echo -n "是否想继续添加: [y/n]:"

read contine

if [ "${contine}" == "n" -o "${contine}" == "N" ]

then

break

fi

done

#######################################################

else

if [ "${num}" == "3" ]

then

while [ "1" == "1" ]

do

clear

echo "---------------------delete ACL----------------------"

echo "(1) 针对源ip删除"

echo "(2) 针对端口删除"

echo "(3) 针对有端口和服务的ACL删除"

echo "(4) 自定义删除"

echo "(5) 退回上一级"

echo "-------------------------------------------------"

echo -n "enter you chose[0-5]:"

read aclnum

if [ "${aclnum}" == "1" ]

then

read ip

iptables -D INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT

echo "iptables -D INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "2" ]

then

read port

iptables -D INPUT -p tcp --dport ${port} -j ACCEPT

echo "iptables -D INPUT -p tcp --dport ${port} -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "3" ]

then

read ip port

iptables -D INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT

echo "iptables -D INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT" >>fw.sh

# service iptables save

elif [ "${aclnum}" == "4" ]

then

read deleteacl

`${deleteacl}`

service iptables save

else

break

fi

echo -n "是否想继续添加: [y/n]:"

read contine

if [ "${contine}" == "n" -o "${contine}" == "N" ]

then

break

fi

done

###################################################################

else

if [ "${num}" == "4" ]

then

echo -e "`service iptables stop&` "

else

if [ "${num}" == "5" ]

then

echo -e "`service iptables save&`"

else

if [ "${num}" == "6" ]

then

echo -e "`service iptables status&`"

else

if [ "${num}" == "7" ]

then

while [ "1" == "1" ]

do

clear

echo "---------------------list ACL----------------------"

echo "(1) 查看当前正在使用的规则集"

echo "(2) 查看每个策略或每条规则、每条链的简单流量统计"

echo "(3) 查看NAT表"

echo "(4) 自定义查看"

echo "(5) 退回上一级"

echo "-------------------------------------------------"

echo -n "enter you chose[0-5]:"

read aclnum

if [ "${aclnum}" == "1" ]

then

iptables -L

elif [ "${aclnum}" == "2" ]

then

iptables -L -n -v

elif [ "${aclnum}" == "3" ]

then

iptables -L -t nat

elif [ "${aclnum}" == "4" ]

then

read listacl

`${listacl}`

else

break

fi

echo -n "是否想继续添加: [y/n]:"

read contine

if [ "${contine}" == "n" -o "${contine}" == "N" ]

then

break

fi

done

################################################

else

exit

fi

fi

fi

fi

fi

fi

fi

fi

echo -n "Do you contine [y/n]:"

read contine

if [ "${contine}" == "n" -o "${contine}" == "N" ]

then

exit

fi

done

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