本文实例讲述了C#判断一天、一年已经过了百分之多少的方法。分享给大家供大家参考。具体如下：

这里写了四个函数，分别是

1.判断当前时间过了今天的百分之多少 static double DayTimePassed()

2.判断指定时间过了当日的百分之多少 static double DayTimePassed(DateTime dt)

3.判断当前时间过了今年的百分之多少 static double YearTimePassed()

4.判断指定时间过了当年的百分之多少 static double YearTimePassed(DateTime dt)

一、函数代码

/// <summary> /// 判断当前时间过了今天的百分之多少 /// </summary> /// <returns></returns> static double DayTimePassed() { DateTime dt = DateTime.Now; double Numerator = dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second; double Denominator = 24 * 60 * 60; return Numerator / Denominator; } /// <summary> /// 判断指定时间过了当日的百分之多少 /// </summary> /// <param name="dt"></param> /// <returns></returns> static double DayTimePassed(DateTime dt) { double Numerator = dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second; double Denominator = 24 * 60 * 60; return Numerator / Denominator; } /// <summary> /// 判断当前时间过了今年的百分之多少 /// </summary> /// <returns></returns> static double YearTimePassed() { DateTime dt = DateTime.Now; double Numerator = dt.DayOfYear * 24 * 60 * 60 + dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second; double Denominator = (DateTime.IsLeapYear(dt.Year) ? 366 : 365) * 24 * 60 * 60; return Numerator / Denominator; } /// <summary> /// 判断指定时间过了当年的百分之多少 /// </summary> /// <param name="dt"></param> /// <returns></returns> static double YearTimePassed(DateTime dt) { double Numerator = dt.DayOfYear * 24 * 60 * 60 + dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second; double Denominator = (DateTime.IsLeapYear(dt.Year) ? 366 : 365) * 24 * 60 * 60; return Numerator / Denominator; }

二、Main函数调用

static void Main(string[] args) { Console.WriteLine(DateTime.Now.ToString()); Console.WriteLine("Day: " + DayTimePassed().ToString("P")); Console.WriteLine("Day: " + DayTimePassed(DateTime.Now).ToString("P")); Console.WriteLine("Year: " + YearTimePassed().ToString("P")); Console.WriteLine("Year: " + YearTimePassed(DateTime.Now).ToString("P")); Console.ReadLine(); }

三、运行结果

希望本文所述对大家的C#程序设计有所帮助。