代码如下所示：

复制代码 代码如下:

/************************************************************************/

/* 给定两个字符串s1和s2，要求判定s2是否能被s1做循环移位得到的字符串所包含

例如，给定s1 = AABCD, s2 = CDAA,返回true，给定s1 = ABCD， s2 = ACBD，返回false*/

/************************************************************************/

#include "stdafx.h"

#include <iostream>

using namespace std;

//穷举法

int IfRotateContain1(char *str1, const char *str2);

//空间换取时间法

int IfRotateContain2(char *str1, const char *str2);

int _tmain(int argc, _TCHAR* argv[])

{

char str1[] = "AABBCD";

char str2[] = "CDAA";

int ret1 = IfRotateContain1(str1, str2);

int ret2 = IfRotateContain2(str1, str2);

cout << ret1 << endl;

cout << ret2 << endl;

return 0;

}

int IfRotateContain1( char *str1, const char *str2 )

{

int len = strlen(str1);

for (int i = 0; i < len; i++)

{

char temchar = str1[0];

for (int j = 0;j < len-1; j++)

{

str1[j] = str1[j+1];

}

str1[len-1] = temchar;

if (strstr(str1, str2) )

{

return 1;

}

}

return 0;

}

int IfRotateContain2( char *str1, const char *str2 )

{

int len = strlen(str1);

char *p = new char[len*2+1];

for (int i = 0; i < len; i++)

{

p[i] = str1[i];

p[i+len] = str1[i];

}

for (int j = 0; j < len*2; j++)

{

if (strstr(str1, str2))

{

return 1;

}

}

delete [] p;

return 0;

}